ATOC 3500                                         Lecture 6

Acid Rain: Review of pH & Acid/Base Chemistry



Recap of Lecture 5

Objectives for Lecture 6
 

Overview of Acid Rain Phenomenon
 
 


 

The Basics: Acidity and pH
 

Need a refresher on acid/base chemistry? Try this tutorial!
 
 

What is an acid?

A substance that, when dissolved in water, increases the concentration of hydrogen ion (H+). Similarly a base is a substance that, when dissolved in water, increases the concentration of the hydroxide ion (OH-).
 
 

In an acidic solution, [H+] > 1.00 x 10-7 M (M º moles L-1)

In a neutral solution, [H+] = 1.00 x 10-7 M

In a basic solution, [H+] < 1.00 x 10-7 M
 
 

The pH scale

For convenience, the pH (potential hydrogen) scale was developed. This relates the [H+] to an easier number to manipulate, via:

pH = -log10[H+]






So, if the [H+] of a solution is 3 x 10-4 M, the pH would be

pH = -log10(3 x 10-4) = 3.52







Self-ionization of water

To some small degree, water will break down into ions:

H2O « H+ + OH-                     Kw = 1 x 10-14


Where Kw = [H+][OH-], the ion product or equilibrium constant for this reaction.

One can show from this relationship that

pH + pOH = 14.00






Problem: The pH of blood is 7.40. What is the hydrogen ion concentration? What is the hydroxide ion concentration?

 pH = -log[H+], so [H+] = 10-pH

[H+] = 10-7.4 = 3.98 x 10-8 M

To determine the [OH-], one can take either of two paths:

(a.) pH + pOH = 14.0, so pOH = 14.0 - pH = 6.6
     Then [OH-] = 10-pOH = 10-6.6 = 2.51 x 10-7 M

(b.) [H+][OH-] = 1 x 10-14, so [OH-] = 1 x 10-14/[H+]
     Then [OH-] = 1 x 10-14/3.98 x 10-8 = 2.51 x 10-7 M
 
 

Acids (and Bases) in Water
 
 

Let’s take a generic acid, HA:

HA(aq) + H2O(l)« H3O+(aq)+ A- (aq)

K = [H3O+][A-]/[H2O][HA]

Since the water concentration does not change, it can be removed from the equation:

Ka = K[H2O] = [H3O+][A-]/[HA]

The chemical equation is typically shortened to read:

HA(aq)« H+(aq)+ A- (aq)

Ka = [H+][A-]/[HA]

Problem: A 0.01 M solution of hydrofluoric acid (HF) is used in an experiment. If Ka = 6.8 x 10-4, what is the pH of this solution?
 
 

HF « H+(aq) + F- (aq)

initial: 0.01       0         0

change:     -x        +x       +x

final: 0.01-x       x         x

Then,

Ka = [H+][F-]/[HF]

6.8 x 10-4 = x2/0.01-x

If x is small compared to 0.01, we can disregard it in the denominator.

x2 = 6.8 x 10-6
x = 2.61 x 10-3 M

pH = -log [2.61 x 10-3] = 2.58






Atmospheric Aqueous Chemistry

G(g) + H2O(l)« GH(aq)                         K = [GH]/pG

Problem: Nitrogen oxides can interact with water to produce nitrous acid:

NO(g) + H2O(l)« HNO2(aq)                          K1 = 6.5 x 10-2 M atm-1

HNO2(aq)« H+ (aq) + NO2- (aq)                K2 = 4.5 x 10-4 M

Suppose there were a raindrop in contact with these gases; what would its pH be? [NO = 1 x 10-9 atm]
 

First, set up equilibrium expressions for the two processes:

K1 = [HNO2]/PNO                                            K = [H+][NO2-]/[HNO2]

Both expressions contain [HNO2], so we can solve one and substitute into the other:

[HNO2] = K1 PNO ; then K = [H+][NO2-]/K1 PNO

However, this still leaves us with an equation with two unknowns. From the second chemical reaction, we can see that for every H+, we must have an NO2-. In other words, [H+] = [NO2-]. This allows us to simplify the equation for K2 to:

K = [H+][H+]/K1 PNO

Solving for [H+]:

[H+]2 = K2 K1 PNO

[H+] = (K2 K1 PNO )1/2

[H+] = [(6.5 x 10-2 M atm-1)(4.5 x 10-4M)(1 x 10-9 atm)]1/2 = 1.7 x 10-7 M

pH = -log[H+] = -log[1.7 x 10-7] = 6.77







Problem: Vitamin C (ascorbic acid) is a diprotic acid, H2C6H6O6. What is the pH of a 0.10 M solution? How much ascorbate (C6H6O62-) is in solution? K1 = 7.9 x 10-5 and K2 = 1.6 x 10-12
 

Try this one at home... first part of the problem is similar to the HF problem above. The second part is more challenging. Answers given in next lecture.
 
 
 
 
 

What are the acids in the atmosphere?

Inorganic acids

SO2 + OH + M ® HSO3 + M

HSO3 + O2 ® HO2 + SO3

SO3 + H2O ® H2SO4

NO2 + OH + M ® HNO3 + M
CO2 + H2O « H2CO3
SO2 + H2O « H2SO3




Organic acids - typically biological in origin

What’s in acid rain?

Short answer – it depends on the location!!

North America:

Mostly sulfate (SO42-), followed by nitrate (NO3-) and chloride (Cl-).

Some regional dependence – more chloride near coasts, more nitrate in heavily polluted areas (such as LA)

Cations (to balance charge): Na+, Ca2+, NH4+

Europe:

Similar to the US

China:

In some regions, acidity neutralized by alkaline dusts from the central desert.

Otherwise, afflicted with the same problems as industrialized areas.

Remote regions: (northern Canada, central Australia) Dominant acid is sulfuric, but source is biological, not industrial (tested with isotope studies).